Guriddo » Topic: Bug in viewgridrow with spaces in column name?

Bug in viewgridrow with spaces in column name?

Guriddo
Bug in viewgridrow with spaces in column name?

This topic has 8 replies, 3 voices, and was last updated 14 years, 2 months ago by OlegK.

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February 9, 2011 at 7:52 pm #78052

wayne@octavient.net
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I'm using the tableToGrid feature, along with the viewGridRow feature.
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Viewing 8 replies - 1 through 8 (of 8 total)

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February 9, 2011 at 11:47 pm #97336

OlegK
Participant

Hello,

I posted the answer on your question here. The usage of ids having blanks in
elements is the same as the usage of name and index properties of colModel with the blanks inside. It is wrong. Just remove the ids from elements or use the values without blanks.

Best regards
Oleg

January 6, 2012 at 11:22 pm #99319

earachefl
Participant

Oleg, I have to say that I consider this to be a design flaw. We shouldn't have to follow variable naming constraints for our titles. If spaces in the IDs that are created are a no-no, why not have jqgrid insert underscores when it creates the IDs?

January 7, 2012 at 2:40 am #99321

OlegK
Participant

Your problem is that you use tableToGrid plugin insted of the usage of jqGrid directly. If you need use titel having blanks you should use colNames option of jqGrid (or the same option of tableToGrid) instead of the usage of ids having blanks.

Best regards
Oleg

January 10, 2012 at 3:06 pm #99327

earachefl
Participant

I decided to hack viewGridRow() instead. I added this line:

nm = nm.replace(' ', '_');

in two places; first between these two lines in function createData():

setme = false;

January 10, 2012 at 4:10 pm #99330

OlegK
Participant

If you want modify the code you should better use $.jgrid.jqID instead of replacement of blanks to undescores. The function $.jgrid.jqID are used in the most places of jqGrid code, but still not everywhere. The problem it very easy. It one have meta-characters as the part of id and one want to use the id as a part of the jQuery selector one have to escape the characters. The method $.jgrid.jqID do exactly the job.

Regards
Oleg

February 7, 2012 at 7:44 pm #99460

earachefl
Participant

Oleg, I'm not understanding how to use $.jgrid.jqID to accomplish this. Is this separate from the grid initialization? How is it supposed to be called? I've tried adding:

jQuery.jgrid.jqID(' ');
but this doesn't seem to have any affect.

Any help would be greatly appreciated.

February 7, 2012 at 9:32 pm #99461

earachefl
Participant

Oleg, I just realized that you meant to modify the regex string inside jqID() to include spaces. That seems to do the trick.

February 8, 2012 at 12:00 pm #99463

OlegK
Participant

Yes, it's what I mean. Pobably I expressed me not clear enough before. In general one can excape or use a numerical code of any ISO 10646 character (see here) used in the selector.

You can use code like

$.extend($.jgrid, {
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