Guriddo » Topic: Example how to use addJSONData

Example how to use addJSONData

Guriddo
Example how to use addJSONData

This topic has 5 replies, 2 voices, and was last updated 17 years, 4 months ago by tony.

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March 19, 2009 at 12:45 pm #73016

anthonyb
Participant

I can't get addJSONData to work. I'm doing something very simple which should work in theory. What's wrong with this piece of code?
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March 21, 2009 at 11:36 am #85981

tony
Keymaster

Hello,

Do not use JSON.parse – just send the string

Regards

Tony

March 23, 2009 at 6:58 am #86003

anthonyb
Participant

Hi Tony. Thanks for your reply but it doesn't seem to work. It's a very simple example. Have you tried it on your own machine? If so, could you post the exact code you're using? I'm using the lastest version of jqGrid.

March 24, 2009 at 2:23 am #86018

tony
Keymaster

Hello,

Look at the examples – If I look right now you should do:

eval and not parse – i.e

$(”#list”)[0].addJSONData(eval(“(“+mystring+”)”));

Regards

Tony

March 24, 2009 at 12:42 pm #86042

anthonyb
Participant

I've looked at the examples. It's still does not work. What I don't undestand is that yesterday you said:”Do not use JSON.parse – just send the string”. Now you say “use eval and not parse”. So, shall I just send the string or shall I use eval?

Have you actually tried the example on your machine? If so, can you post the working code?

Thanks.

March 26, 2009 at 3:34 am #86075

tony
Keymaster

Hello Anthony,

Sorry, but some time I do not have access to jqGrid code in order to answer exactly. Thanks for this – I will remember – when I'm not sure I will not answer.

Look at New in version 3.3 -> Data type as function

Here we have:

..jqGrid({

…

datatype : function (pdata) {

$.ajax({

url:'server.php?q=2',

data:pdata,

dataType:”json”,

complete: function(jsondata,stat)

{ if(stat==”success”) {

var thegrid = jQuery(“#listdt”)[0];

thegrid.addJSONData(eval(“(“+jsondata.responseText+”)”))

}

}

});

},

…

});

Does this help?

Best Regards

Tony
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