Hello,
It is a very naice way to do this.
Regards
Tony
Hello,
Look at the available methods in cell editing. Maybe you can use the getChangedCells method.
Regards
Tony
Hello,
It is difficult to me to understand what you mean.
onSelectRow does nothing to do with inline edit. It is just a way to call editing.
If yo do not pass a parameter to t onSelectRow you will not have this. I fo not understand waht you mean.
Regards
Tony
Hello Marco,
Thanks. Found it. It is a bug.
Best Regards
Tony
Hello,
Thanks. Fixed in GitHub
Best Regards
Tony
Hello,
You should not define the tree coulms in colModel. The jqGrid does this automatically
for you. Also the columns parent_id and isLeaf in colModel are not needed. By default these coulms are not editable and if you want to edit them use setColProp after the grid is constructed and before the first edit. See docs which event is the best for your requierments
Regards
Tony
Hello,
Thanks. Fixed. A better is to fix when data is pushed in the savedRow – i.e. I apply this to ths value in the savedRow only.
Best Regards
Tony
Hello,
I think that this is the problem. Instead of the scroll the ids should be uniquie.
Regards
Tony
Hello,
To be a honest it was a difficult for me to understand what work and waht not in you case, but anyway – this is a bug and it is corrected. Will publish soon new build
Regards
Tony
Hello,
Java Script is case sensitive. You have not sonsitent definition and returned data – in sense of case sensitivity.
Regards
Tony
Hello Lotte,
My simple answer is: Again refer to the docs
http://www.secondpersonplural.ca/jqgriddocs/_2ej16ksnu.htm
Best Regards
Tony
Hello
Which row do you want to save:
jQuery('#todo').saveRow
Hello again,
sorry put a save button before finishing
you should
var response = “{ [{'id':'5','name':'john smith'}] }“;
and configure jsonReader for this.
Please first refer to documentatin before posting issue.
Also you can use the addJsonData in the way that you have – i.e not in datatype function.
Best Regards
Tony
Hello,
Check your datepicker configuration.
Hello,
var response = “[{'id':'5','name':'john smith'}]“;
jQuery(”#list2″).jqGrid({
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