OlegKHello!
In jqGrid the rowid is the id of the
Best regards
Oleg
P.S. I thought a little more about the spaces in the ids and have a suggestion. One can here read the following: “Any character (except a hexadecimal digit, linefeed, carriage return, or form feed) can be escaped with a backslash to remove its special meaning.“. So I tried to escape the space (U+0020) charackter and it seems gives very good results. Look at the demo. It seems if one modify the code of jqID function of jqGrid to
jqID : function(sid){
OlegKHello jfernandezrico,
You can improve the visibility of the pager if you exactute the following code
$($("#listGrupos")[0].p.pager+"_left").hide();
which will hide the empty div with id=”pagerGrupos_left” existing on the left part of the pager.
Best regards
Oleg
OlegKOlegKIf you don't fix validation errors then you have much more probability that your page will look different in different web browsers or different versions of the same browser. It means that the web browser try to guess what you mean. So I try to validate my pages always in http://validator.w3.org/
OlegKSorry for misunderstanding, but the tree grid filtering can't be used locally. I supposed that in case of 2000 rows you use server based data and can implement server based data filtering. I wrote the same as the answer on your question on the stackoverflow.
Regards
Oleg
OlegKYou can fix the problem if you include CSS
body { font-size: 75%; }
on your page. Moreover you should always write the page in one HTML or XHTML dialect which you define in the corresponding <!DOCTYPE
OlegKHello vasanth,
you asked about the existing features of tree grid. I unswered you. You wrote that you have 2000 records, but you don't describe how the data is organized (deep level, how many subnodes you have for one node). In the standard implementation of the tree grid if the user click on the node to see the childrens of the node the jqGrid send the request to the server which include the id of the expanding node. So the server should send back all child nodes. I hope it will be not 1000 items. So I recomend you just set rowNum
OlegKWhat do you mean under BREAK? Is it LF, CR LF,
or
? If you has line feed ('n') inside of the data you can replace it to
. The grid data can contain not only pure data. If you don't use autoencode:true jqGrid option you can insert in the grid data any HTML code.
Best regards
Oleg
OlegKThe performance of the client sorting depend mostly from the performance of the JavaScript, so depend on the browser which you use. For example Google Chrome is much better as IE6 in the JavaScript performance. In any way you should understand that your requirement client side instead of the server side makes the sorting at least 1000 times slowly. Is it really what your customer want?
Do you use at least client side paging? It can improve the performance dramatically. Look at the old demos this and this and compare the sorting performance. Which web browser you use? Do you use gridview: true
OlegKIt is difficult to guess not haven seen the page about which you wrote. Could you post the URL to the page having the problem or post the full HTML page which can be used to reproduce your problem?
OlegKYou should do following:
OlegKYou should call $(“#grid”).jqGrid('bindKeys', {…});
OlegKSorry, but I can't follow you. I don't use PHP, so I don't need to download jqgrid_demo3.8. You asked to help you to display the Add, Edit and Delete Icons first on the Navigator. I explain you your error.
You wrote about some my (?) blank screen
OlegKIf you use
jQuery("#list").jqGrid('navGrid','#pager',{parameters},prmEdit, prmAdd, prmDel, prmSearch, prmView);
you should define the variables parameters, prmEdit, prmAdd, prmDel, prmSearch, prmView before. If you want to use the standard settings you can just use
jQuery("#list").jqGrid('navGrid','#pager');
Regards
Oleg
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