I have the same problem, but I found soulution for this. There is only one problem – my soulution is not good one….

at first, I use grid.base.js, not jquery.jqGrid.min.js

There is line like this (572):$(“.ui-paging-info”,ts.p.pager).html($.jgrid.format(ts.p.recordtext,from,to,tot));

This line is start of the problem. When format function is called ($.jgrid.format(ts.p.recordtext,from,to,tot)), the first argument – ts.p.recordtext –

seems you should attache jquery.searchFilter.css from http://github.com/tonytomov/jqGrid/tree/master/css/

…

Actually you can look at jquery.searchFilter.js.

Regards

Tony

Thank you

Hello,

I'm using jqGrid in an application based on ZendFramework

Hello Tony

I can see that many developers have similiar problems (additional id in showlink).

Maybe You should think about some hidden(or not) fields in grid to store such an id.

I suggest another parameter in formatoptions.

Let's name it idValue (or idColumn) and set there name of id column.

If You would like I can write a little piece of code for You to make great jqGrid working like this.

Regard,

Piotr Roznicki