Hello,

First of all jqGrid is a very nice plugin!

my jqGrid setup works without hitch. I have also put together functions that create a form based on column headers and exports the headers and data in tab/csv/excel format from the jqGrid….

I would like to move off this page the form that allows a user to select which columns they want to export to a popup window. The idea being that other pages that use jqGrid can just call this popup window.

I can access the parent table from the child popup with something like:

$(window.opener.document.getElementById('list')).attr('id')

and it displays the table id.

When I try to retrieve the data with a jqGrid function:

jQuery(window.opener.document.getElementById('list')).getDataIDs()

my firebug gives me ……getDataIDs is not a function.

Again I don't believe this is a jqGrid error (as it works fine on 1 page scenario) but my use of javascript in general – just hoping someone may know a work around specific to jqGrid or the explanation why it is giving me this error message.

Closest message I saw to my question was the clone idea – not sure about that in this case.

I am trying to use the existing jqGrid data & functions to avoid querying the database a 2nd time for the same xml information and a duplicate jqGrid….

Thank you,