Hello,
Mybe you will need
Hello,
If I understand right you want to hide the subgrid column – simple do not use subgrid.
Regards
Tony
Hello,
Thanks – It seem to be another bug.
Tony
Hello,
No. Check the formu and documentation
Regards
Tony
Hello,
See this
http://www.trirand.com/blog/?page_id=18/help/adding-buttons-to-a-field/page-1
Replace the input button with checkbox
For the second do not understand – dor you mean subgrid?
Regards
Tony
Hello,
Using custom formatter
mybuttonadd = function(cellvalue, opt, roawdata) {
var mybutton = “”;
return cellval+mybutton; // or mybutton+cellvalue
}
function myfunc(id)
{
alert(id);
}
then you can in colModel
Hello
(If I understand right)
$(“.ui-jqgrid-htable tr:first”,”#gview_”+mygridid).hide();
where the mygridid is the grid it.
Regatds
Tony
Hello,
At end to resolve this – PLEASE HOW DO YOU CHECK THAT THIS PARAMETER IS FALSE SERVER SIDE?
If you look in the demo you maybe will check this
php code
$myserch = $_GET[“_search”];
if($mysearch == “true”) {…..}
AND NOT
if($mysearch)
Regards
P.S. The best way to check this is to see the posted parameters in FireBug console.
Regards
Tony
Hello,
Not sure what you mean with this – where to add in header, in the subgrid body, in the subgrid row or ….
Regards
Tony
Hello,
I recommend you to have a uniquie id for every row.
Regards
Tony
Hello,
How do you use this?
Also you can use the dataUrl option and load direct a html select content
Regards
Tony
Hello,
Direct this is not possible, but you can use GridUnload to destroy the grid and load the new data with another configuration.
Regards
Tony
Hello,
I do not see any problem. Suppose your second column should have sparkline,
then you can $(“tr#myid td:eq(1)”, “#mygrid”).sparkline(). Also the same approach can be used in afterInsertRow event
Regards
Tony
Hello,
Thanks.
Regards
Tony
Hello,
1. I recommend (it is not important but) load first the ui css first and then ui.jqgrid.css
2. Your ui.jqgrid.css is not complete. Please use the one from css directory and not from src css
Regards
Tony
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