Hello,

It seems that you do not have defined the custom_value functio which should return the value from the custom created element. This function should be present in order to work the posting. See the demo What is new in 3.6. and read here :

http://www.trirand.com/jqgridwiki/doku.php?id=wiki:common_rules#edittype

Best Regards

Tony

Hello,

Thanks.

In order to work this you should

1. Be a sure that when you download the grid you marked the last item in the selection – jQuiery UI addons. The easy way to check this is when you open the jquery.jqGrid.min.js file and look in the Modules row at the beggining – the grid.jqueryui.js

Hello,

Not sure if this is a bug. Please check your code again and what you try to do. Also check your response. If you populate the grid manually with json data you will need to care about this.

Regards

Tony

Hello,

The way what you do it – it will not work. Be a sure that you read carfully the documentation – what we need for custom data type.

To work this you should create a custom element table in the form. The custom value function should return some dummy value.

Use onInitializeForm to create the grid in the form.

Regards

Tony

Mark,

Here is another similar IMHO:

Forum

I will take a look at the problem these days.

Tony

Hello,

maybe you will need to use SET NAMES before the requesting data in mysql

Regards

Tony

Hello,

Here is the description:

“rowelem is the element from the response. If the data is xml this is the xml element of the row; if the data is json this is array containing all the data for the row”

Is something that is not clear?

Hello,

Currently no, but it is a good sugestion for the next releases.

Regards

Tony