Hello,
Just tested your example.
Little errors in the data provided here – the table must have a TH element in order to work this properly.
I changed the first row from TD to TH
Remove the option loadonce :true and everthing will work.
Best Regards
Tony
If you use a pager – there is a such function – if no records we put usually at botom right of the grid – No records to view.
Regards
Try to install the development version – described here
http://www.trirand.com/jqgridwiki/doku.php?id=wiki:how_to_install#development_installation
Then from where is this input tag? Into the code provide from you I do not see any method from inline edit
Use afterInserRow event to add a class(style) to particular row.
This is not correct
colModel :[
{name:”stateId”, index:”stateId”, width:70},
{name:”stateCde”, index:”stateCde”, width:100},
{name:”stateNameTxt”, index:”stateNameTxt”, width:200, align:”left”}, <===== ERROR IN IE
],
Since you do the string from ajax check your response from server. I think this ios the problem
This is possible and often used by me.
The idea is to use the onInitializeForm which is called only once when the form is created.
The id if every input correspond to the name from colModel
Setting id is recommended for proper work. Also you can generate your own id using random generator. The fasted way to every dom manipulation is to query it by ID.
Just set sortable option to false
Regasds
This feature is just added in the GitHub.
http://github.com/tonytomov/jqGrid/commit/c913664ba19834bc1ae0efeb696b5c261f3f468d
and will be available in 3.6.3 soon.
Be a sure that you have uniquie id in the grid. One possible reason is that all your rows have the same id.
beforeSearch: function() {
var posted_data = $(“#mygrid”).jqGrid('getGridParam,'postData');
if(posted_data.address == 'myadderss') return true;
else return false;
}
Manipulating =>Grid data – the click on update amounts link.
Stay connected with us in your favorite flavor!
Copyright 2014 TriRand LtdAll Rights ReservedRSS
