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January 2, 2017 at 4:00 pm in reply to: Guriddo PHP Suito documentation #125741

guriddo.support

Participant

Hello,

As for now use this link

It is not up to date. All the new functions and features are described in the whant is new when you download the licensed version.

Kind Regards,
Will

Guriddo Support Team

December 27, 2016 at 12:00 pm in reply to: How do you have jqGrid re-calculated the column width? #125738

guriddo.support

Participant

Hello,

Using a console to set something is not a prefered way.
The method work for us – this is tested.

Setting the column to width 20 will not work. The min column width is defined in minColWidth and default to 33.

Your example will work if you define two buttons and within document ready do:

        $(document).ready(function () {
            $(&quot;#jqGrid&quot;).jqGrid({...});
			$(&quot;#increase&quot;).on(&#039;click&#039;, function() {
				$(&quot;#jqGrid&quot;).jqGrid(&#039;resizeColumn&#039;,  &#039;ProductName&#039;, 200 );
			});
			$(&quot;#decrease&quot;).on(&#039;click&#039;, function() {
				$(&quot;#jqGrid&quot;).jqGrid(&#039;resizeColumn&#039;,  &#039;ProductName&#039;, 80 );
			});
...

$(document).ready(function () {

$("#jqGrid").jqGrid({...});

$("#increase").on('click', function() {

$("#jqGrid").jqGrid('resizeColumn', 'ProductName', 200 );

});

$("#decrease").on('click', function() {

$("#jqGrid").jqGrid('resizeColumn', 'ProductName', 80 );

});

...

Kind Regards,

Will

Guriddo Support Team

December 19, 2016 at 1:28 pm in reply to: How do you have jqGrid re-calculated the column width? #125736

guriddo.support

Participant

Hello,

You should execute the method associated with the grid and not to the container.

The expression :

...
$(&#039;.demo-jqgrid-container&#039;).jqGrid(&#039;resizeColumn&#039;, &#039;categoryName&#039;, 60);
...

...

$('.demo-jqgrid-container').jqGrid('resizeColumn', 'categoryName', 60);

...

is not correct.

The correct code is:

...
$(&#039;#demo-jqgrid&#039;).jqGrid(&#039;resizeColumn&#039;, &#039;categoryName&#039;, 60);
...

...

$('#demo-jqgrid').jqGrid('resizeColumn', 'categoryName', 60);

...

Please note the difference

Kind Regards
Will

Guriddo Support Team

December 16, 2016 at 10:46 am in reply to: Load and Save state without data #125734

guriddo.support

Participant

Hello,

Unfortunately this is not possible at the moment, but we think this is a good feature to included in the code.

We will make the needed changes and let you know. We hope to be ready for Monday 19

Kind Regards,

Will

Guriddo Support Team

December 15, 2016 at 10:44 am in reply to: How do you have jqGrid re-calculated the column width? #125732

guriddo.support

Participant

Hello,

You can use getGridParam method to get the colModel property.

Loop throught this array in which every object has a width Property to get the actual width and use the method resizeColumn with parameters column name(or index) and the new width.

var colModel = $(&quot;#grid&quot;).jqGrid(&#039;getGridParam&#039;, &#039;colModel&#039;);
for( var j = 0; j&lt;colModel.length; j++ ) {
   if( colModel[j].hasOwnProperty( width ) ) {
      var width = parseInt(colModel[j].width,10);
      $(&quot;#grid&quot;).jqGrid(&#039;resizeColumn&#039;, colModel[j].name, width*0.8);
   }
}

var colModel = $("#grid").jqGrid('getGridParam', 'colModel');

for( var j = 0; j<colModel.length; j++ ) {

if( colModel[j].hasOwnProperty( width ) ) {

var width = parseInt(colModel[j].width,10);

$("#grid").jqGrid('resizeColumn', colModel[j].name, width*0.8);

}

Hope this helps

Regards,

Guriddo Support Team

December 14, 2016 at 10:58 am in reply to: How do you have jqGrid re-calculated the column width? #125728

guriddo.support

Participant

Hello,

Not sure that I understand the question. You can use the GridWidth function to set the new width of the grid based on the new settings. The font-size just change the size of the font and not the width

Maybe you want to know how to change the font-size based on the width(this is done via google search)

Kind Regards,

Will

Guriddo Support Team

December 13, 2016 at 9:24 am in reply to: jqGrid PHP and Zend Framework 1 integration #125726

guriddo.support

Participant

Hello,

Unfortunately this is not possible at the moment. Currently when you have the connection object you can write regular SQL query using the SelectCommand as show in the demo.

We will try to investigate, if we can make such kind of integration, but as you know this will take time.

Instead we will just look into the Zend concepts and will let you know if this will be possible at all.

In the mean time you can just experiment with what we have suggested.

Kind Regards,

Will

Guriddo Support Team

December 12, 2016 at 12:55 pm in reply to: jqGrid PHP and Zend Framework 1 integration #125724

guriddo.support

Participant

Hello,

We do not have only PDO, but some other drivers like mysqli, sql server, ado db and etc.

Short – you can not use direct the Zend connection adapter, but….

Suppose the Zend connects using PDO, then if you can extract the connection from the addapter you can pass it. Example:

$dbAdapter = Zend_Registry::get(‘dbAdapter’);

If the connection is stored by example in : $dbAdapter->conn

then you can use this to connect to jqGrid using the standard code.

We are not familiar with Zend, but if you need any help you are welcome.

Kind Regards,
Will

Guriddo Support Team

December 5, 2016 at 12:54 pm in reply to: Loading Data Across Many Tables #125721

guriddo.support

Participant

Hello,

setSelect is not only for drop down, but also for presenting a a data in the grid.

In JavaScript PHP setSelect can be considered as formatter : ‘select’ too (see the options here ).

Just try it does not require a lot of work.

Guriddo Support Team

December 5, 2016 at 11:00 am in reply to: Loading Data Across Many Tables #125717

guriddo.support

Participant

Hello,

If I understand the question right you can use setSelect for these columns.
See the example here . Look at the CustomerID field.

Kind Regards,
Will

Guriddo Support Team

December 5, 2016 at 10:52 am in reply to: jqgrid/jquery ui, dragging column to scroll table? #125715

guriddo.support

Participant

Hello,

Until now without success. Below is the code, which maybe will give you a idea (it is not working)

&amp;nbsp;
            var grid = $(&quot;#jqGrid&quot;).jqGrid({
                url: &#039;data.json&#039;,
                datatype: &quot;json&quot;,
                colModel: [
					{ label: &#039;Category Name&#039;, name: &#039;CategoryName&#039;, width: 100 },
					{ label: &#039;Product Name&#039;, name: &#039;ProductName&#039;, width: 110 },
					{ label: &#039;Country&#039;, name: &#039;Country&#039;, width: 200 },
					{ label: &#039;Price&#039;, name: &#039;Price&#039;, width: 180, sorttype: &#039;integer&#039; },
					// sorttype is used only if the data is loaded locally or loadonce is set to true
					{ label: &#039;Quantity&#039;, name: &#039;Quantity&#039;, width: 180, sorttype: &#039;number&#039; }
                ],
				loadonce: true,
                width: 600,
                height: 200,
                rowNum: 150,
				shrinkToFit : false,
                sortable: { options: {
						//scrollSensitivity : 5,
						forcePlaceholderSize  : true,
						forceHelperSize: true,
						start : function( e, ui) {
							var sc = $(&quot;.ui-jqgrid-hdiv &quot;);
							sc.css(&#039;overflow-x&#039;,&#039;auto&#039;);
						},
						stop : function( ev, ui) {
							var sc = $(&quot;.ui-jqgrid-hdiv &quot;).scrollLeft();
							//console.log(sc);
							grid[0].grid.bDiv.scrollLeft = sc;
							//console.log(grid[0].grid.bDiv.scrollLeft);
							$(&quot;.ui-jqgrid-hdiv &quot;).css(&#039;overflow-x&#039;,&#039;hidden&#039;);
						}
					} },
                pager: &quot;#jqGridPager&quot;
            });

&nbsp;

var grid = $("#jqGrid").jqGrid({

url: 'data.json',

datatype: "json",

colModel: [

{ label: 'Category Name', name: 'CategoryName', width: 100 },

{ label: 'Product Name', name: 'ProductName', width: 110 },

{ label: 'Country', name: 'Country', width: 200 },

{ label: 'Price', name: 'Price', width: 180, sorttype: 'integer' },

// sorttype is used only if the data is loaded locally or loadonce is set to true

{ label: 'Quantity', name: 'Quantity', width: 180, sorttype: 'number' }

loadonce: true,

width: 600,

height: 200,

rowNum: 150,

shrinkToFit : false,

sortable: { options: {

//scrollSensitivity : 5,

forcePlaceholderSize : true,

forceHelperSize: true,

start : function( e, ui) {

var sc = $(".ui-jqgrid-hdiv ");

sc.css('overflow-x','auto');

stop : function( ev, ui) {

var sc = $(".ui-jqgrid-hdiv ").scrollLeft();

//console.log(sc);

grid[0].grid.bDiv.scrollLeft = sc;

//console.log(grid[0].grid.bDiv.scrollLeft);

$(".ui-jqgrid-hdiv ").css('overflow-x','hidden');

}

} },

pager: "#jqGridPager"

});

Kind Regards,
Will

This reply was modified 9 years, 4 months ago by guriddo.support.

Guriddo Support Team

November 27, 2016 at 3:28 pm in reply to: Treegrid load expanded problem #125707

guriddo.support

Participant

Hello,

Sorry that I initially do not understand the problem in details.

Definitely this is a bug. Thank you.

We have fixed it in GitHub

You can grab the new build from GitHub and test.

Please let us know if the bug is fixed for you.

Kind Regards,
Will

Guriddo Support Team

November 23, 2016 at 10:17 am in reply to: Treegrid load expanded problem #125697

guriddo.support

Participant

Hello,

Sorry I missed this.

It important to say, that the data field expanded should be set to true.
In your case it is set to false. When we change this property to true it is working as expected in our environment.

If you have difficulties we can publish your demo online.

Kind Regards
Will

Guriddo Support Team

November 23, 2016 at 10:05 am in reply to: Combining multiple JSON feeds #125696

guriddo.support

Participant

Perhaps you put a object as data instead of array.
if you do

mydata = []; //array
//and then 

mydata.push( {
		&quot;LGICUS01OperationResponse&quot;: {
			&quot;ca&quot;: {
				&quot;ca_phone_mobile&quot;: &quot;123&quot;,
				&quot;ca_request_id&quot;: &quot;01ICUS&quot;,
				&quot;ca_return_code&quot;: 0,
				&quot;ca_dob&quot;: &quot;30.09.1965&quot;,
				&quot;ca_last_name&quot;: &quot;Tracey&quot;,
				&quot;ca_num_policies&quot;: 0,
				&quot;ca_phone_home&quot;: &quot;&quot;,
				&quot;ca_email_address&quot;: &quot;REFROOM@TBHOLDINGS.COM&quot;,
				&quot;ca_house_name&quot;: &quot;Tracey Island&quot;,
				&quot;ca_policy_data&quot;: &quot;&quot;,
				&quot;ca_customer_num&quot;: 3,
				&quot;ca_first_name&quot;: &quot;Scott1&quot;,
				&quot;ca_house_num&quot;: &quot;&quot;,
				&quot;ca_postcode&quot;: &quot;TB14TV&quot;
			}
		}
	});

mydata = []; //array

//and then

mydata.push( {

"LGICUS01OperationResponse": {

"ca": {

"ca_phone_mobile": "123",

"ca_request_id": "01ICUS",

"ca_return_code": 0,

"ca_dob": "30.09.1965",

"ca_last_name": "Tracey",

"ca_num_policies": 0,

"ca_phone_home": "",

"ca_email_address": "REFROOM@TBHOLDINGS.COM",

"ca_house_name": "Tracey Island",

"ca_policy_data": "",

"ca_customer_num": 3,

"ca_first_name": "Scott1",

"ca_house_num": "",

"ca_postcode": "TB14TV"

}

});

then you will have a array and not a object,

In all cases jqGrid does not tuch the source data it is just stored in the grid parameters.

Regards,
Will

Guriddo Support Team

November 22, 2016 at 10:12 am in reply to: Combining multiple JSON feeds #125693

guriddo.support

Participant

Hello,

for( var k=0; k &lt; postdata.length; k++) 
{
   var row = postdata[k];
   console.log( row.LGICUS01OperationResponse.ca.ca_house_name );
}

for( var k=0; k < postdata.length; k++)

{

var row = postdata[k];

console.log( row.LGICUS01OperationResponse.ca.ca_house_name );

}

Regards
Will

Guriddo Support Team

Author

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Viewing 15 replies - 601 through 615 (of 1,092 total)

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