Thank you for your answer!

But I think the problem isn’t in it, I’m already have idprefix. here’s my grid definitions (sorry for messy).

$(“#EditTimeGrid”).jqGrid({
datatype: “local”,
loadonce: true,
multiselect: false,
data: mainData,
scrollrows: true,
height: “100%”,
colNames: [‘@Resource.ID’, ”, ‘MainID’, ‘FullDate’, ‘@Resource.Date’, ‘@Resource.Day’, ‘DayNum’, ‘@Resource.Project_Category’,
‘@Resource.Start’, ‘@Resource.End’, ‘@Resource.Lunch’, ‘@Resource.BillHours’, ‘@Resource.NonBillHours’, ‘@Resource.TotalHours’,
‘@Resource.Notes’, ”, ‘start’, ‘end’, ”, ”],

…

rowattr: function (rd) {
return { “class”: “boldRow” };
},
rowNum: 10,
//rowList: [5, 10, 20],
//gridview: true,
cellEdit: editMode,
cellsubmit: ‘clientArray’,
ignoreCase: true,
rownumbers: true,
// sortname: ‘DayAsNumber’,
// sortorder: “asc”,
viewrecords: true,
autoencode: true,
footerrow: true
, idPrefix: “s_”

, subGrid: true

 

and for subgrid

$subgrid.jqGrid({
datatype: “local”
, scrollrows: true
, multiselect: false
, data: sd

…

, height: “100%”
, rowNum: 10
, autoencode: true
//gridview: true,
, cellEdit: editMode
, cellsubmit: ‘clientArray’
, idPrefix: rowId + “_”

 

I’ve made some investigation and found a function in the jquery.jqgrid.src.js file

(line 10282)

.keydown(function (e) {

…

switch (kdir) {
case 38:
if ($t.p.iRow – 1 > 0) {
scrollGrid($t.p.iRow-1,$t.p.iCol,’vu’);
$($t).jqGrid(“editCell”,$t.p.iRow-1,$t.p.iCol,false);
}
break;

 

If we press right or left arrow, we found next visible column, but if we pressed up or down key we just go to next or previous row, even if it’s a subgrid’s invisible row.  Maybe I’m wrong with my opinions.